The mean fatigue lives of [0=90]S E-glass fiber–epoxy laminates at maximum stress levels of 56,000 and 35,000 psi are 1,500 and 172,000, respectively. The static tensile strength of this material is 65,000 psi. Determine the residual static strength of this material after 50% of the fatigue life at each stress level 2. After cycling for 50% of the fatigue life at 35,000 psi, the maximum stress level in a fatigue specimen is increased to 56,000 psi. Estimate the number of cycles the specimen would survive at 56,000 psi 3. If the first stress level is 56,000 psi, which is then followed by 35,000 psi, estimate the number of cycles at the second stress level

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A carbon fiber bundle containing 2000 parallel filaments is being tested in tension. The filament length is 100 mm. The strength distribution of individual filaments is described in Problem P2.5. Compare the mean filament strength and the mean fiber bundle strength. Schematically show the tensile stress–strain diagram of the carbon fiber bundle and compare it with that of the carbon filament. (Note: For a ¼ 6.58, G 1 þ 1 a ffi 0:93.)

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P4.10. The following table* gives the stress-strain data for [0/90/+45]s and [0/90]2s AS-4 carbon fiber-epoxy laminates obtained in a three-rail shear test. Plot the data and determine the shear modulus for each laminate. Compare these values with those predicted by the lamination 143.92 GPa, theory based on the following material properties: E11 E22 11.86 GPa, G12 = 6.68 GPa, and V12 = 0.326. Shear Stress (MPa) [0/90/+45)s [0/90)2s Shear Strain (%) 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 40 91 128.6 155 178 208 232 260 13.6 24.5 37 47.3 54.5 62 65.4 70

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The following longitudinal tensile strength data (in MPa) were obtained for a [0/+45/90], E-glass fiber-epoxy laminate: 518.05, 472.25, 448.50, 560.20, 555.32, 496.95, 526.50, 550.80, 495.08, 500.05, 498.80, 522.64, and 580.70. (a) Determine the average tensile strength, the standard deviation, and coefficient of variation (b) Determine the Weibull parameters for the given strength distribution (c) Using the Weibull parameters in (b), determine the mean strength for the material

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The following longitudinal tensile strength data (in MPa) were obtained for a [0/+45/90], E-glass fiber-epoxy laminate: 518.05, 472.25, 448.50, 560.20, 555.32, 496.95, 526.50, 550.80, 495.08, 500.05, 498.80, 522.64, and 580.70. (a) Determine the average tensile strength, the standard deviation, and coefficient of variation (b) Determine the Weibull parameters for the given strength distribution (c) Using the Weibull parameters in (b), determine the mean strength for the material

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A T-300 carbon fiber-epoxy lamina (Vf = 0.60) with a fiber orientation angle of 45student submitted image, transcription available belowis subjected to a biaxial stress state ofstudent submitted image, transcription available belowxx = 100 MPa andstudent submitted image, transcription available belowyy = -50 MPa. Determine (a) the strains in the x-y directions, (b) the strains in the 1-2 directions, and (c) the stresses in the 1-2 directions.

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P3.27. The material used in the transmission gears of an automobile is an injection-molded nylon 6,6 containing 20 wt% of chopped randomly oriented E-glass fibers. The tensile modulus of this material is 1.25 × 10° psi. In a more demanding application for the transmission gears, the modulus of the material must be 50% higher. An engineer wants to accomplish this by replacing the E-glass fibers with carbon fibers. If the fiber weight fraction remains the same, calculate the length of carbon fibers that must be used to obtain the desired modulus Use the following information in your calculations. (a) For the carbon fiber, Pr= 1.8 g/cm. Ef= 30 × 106 psi, and df= 0.0006 in, and (b) for nylon 6,6, Pm-114 g/cm 3 and Em-0.4 × 106 psi

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