Step-by-Step Solution
Step 1
We are given that the density of the water is ${\rho _w} = 1.94\;{\rm{slug/f}}{{\rm{t}}^3}$
We are asked to determine the density of water in SI units.
Step 2
The mass $1\;{\rm{slug}}$ is equal to $14.59\;{\rm{kg}}$ in SI units, and the length $1\;{\rm{ft}}$ is equal to $0.3048\;{\rm{m}}$.
Step 3
Now, convert the units.\[\begin{array}{c} {\rho _w} = 1.94\;{\rm{slug/f}}{{\rm{t}}^3}\\ = 1.94\;\left( {\frac{{{\rm{slug}}}}{{{\rm{f}}{{\rm{t}}^{\rm{3}}}}}} \right)\left( {\frac{{14.59\;{\rm{kg}}}}{{1\;{\rm{slug}}}}} \right){\left( {\frac{{1\;{\rm{ft}}}}{{0.3048\;{\rm{m}}}}} \right)^3}\\ = 9.99 \times {10^3}\;{{{\rm{kg}}} \mathord{\left/ {\vphantom {{{\rm{kg}}} {{{\rm{m}}^3}}}} \right. } {{{\rm{m}}^3}}} \end{array}\]