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A finned-tube exchanger is used to heat 2.36 m3/s of air (specific heat of 1006 J/kg C) at 1 atm from 15.55 to 29.44°C. Hot water enters the tubes at 82.22°C and the air flows across the tubes, producing an average overall heat transfer coefficient of 227 W/m2C. The total surface area of the exchanger is 9.29m2. Calculate the heat transfer rate (kw) and the exit water temperature.
A finned-tube exchanger is used to heat 2.36 m3/s of air (specific heat of 1006 J/kg C) at 1 atm from 15.55 to 29.44°C. Hot water enters the tubes at 82.22°C and the air flows across the tubes, producing an ...

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A finned-tube exchanger is used to heat 2.36 m3/s of air (specific heat of 1006 J/kg C) at 1 atm from 15.55 to 29.44°C. Hot water enters the tubes at 82.22°C and the air flows across the tubes, producing an average overall heat transfer coefficient of 227 W/m2C. The total surface area of the exchanger is 9.29m2. Calculate the heat transfer rate (kw) and the exit water temperature.
A finned-tube exchanger is used to heat 2.36 m3/s of air (specific heat of 1006 J/kg C) at 1 atm from 15.55 to 29.44°C. Hot water enters the tubes at 82.22°C and the air flows across the tubes, producing an ...

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In a TEMA – E type shell-and-tube exchanger, as shown in the schematic diagram, water enters the shell at 218 °C at a rate of 1.4 kg/s. Engine oil flows through the tubes at a rate of 1.0 kg/s. The inlet and outlet temperatures of the oil are 150 °C and 90 °C, respectively. Determine the surface area of the exchanger by both the LMTD and E-NTU methods if U = 225W / (m ^ 2) * K The specific heats of water and oil are 4.19 and 1.67 J/g K respectively.
5. In a TEMA - E type shell-and-tube exchanger, as shown in the schematic diagram, water enters the shell at 218 °C at a rate of 1.4 kg/s. Engine oil flows through the tubes at a rate of 1.0 kg/s. ...

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Distilled water at a flow rate of 80,000 kg/hr enters an exchanger at 35C and leaves at 25C. The heat will be transferred to 140,000 kg/hr of raw water coming from a supply at 20C. Distilled water is at the ...

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Determine the angular velocity (ω) and angular acceleration (α) of Link DC of the four bar linkage mechanism shown in figure 1. Input link AB rotates at 100 rev/min in anti-clockwise direction with uniform velocity.
Determine the angular velocity (ω) and angular acceleration (α) of Link DC of the four bar linkage mechanism shown in figure 1. Input link AB rotates at 100 rev/min in anti-clockwise direction with uniform velocity.

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A piston, connecting rod and crank mechanism is shown in the diagram. The crank rotates at a constant velocity of 300 rad/s. Find the acceleration of the piston and the angular acceleration of the link BC. The diagram is not drawn to scale. Crank AB is rotating in clockwise direction.
A piston, connecting rod and crank mechanism is shown in the diagram. The crank rotates at a constant velocity of 300 rad/s. Find the acceleration of the piston and the angular acceleration of the link BC. The diagram is not ...

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Find the velocity and acceleration of the piston and the angular velocity and angular acceleration of link AB for the crank slider mechanism shown in figure 2. The crank OA rotates anti-clockwise at 500 rad/min with constant velocity. Point O is fixed.
Find the velocity and acceleration of the piston and the angular velocity and angular acceleration of link AB for the crank slider mechanism shown in figure 2. The crank OA rotates anti-clockwise at 500 rad/min with constant velocity. Point O ...

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Problem: Water decelerates in a diffuser following the relation 𝑉=𝑉𝑜(1−𝐴𝑥2𝐿2) where x is the distance from the start of the diffuser. At time = 0, the flow to the diffuser is turned off slowly and the inlet velocity V0 decays with ...

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For the rotational system shown in Figure P2.22, find the transfer function, G(s) = 0l(s)/T(s). [Sec- tion: 2.7] 2 N-m-s/rad 3 N-m/rad N2= 33 1 kg-m2 HU 00002N3 = 50 nT(1) ne (1) A N, = 11 N4= 101 0.04 N-m-s/rad
For the rotational system shown in Figure P2.22, find the transfer function, G(s) = 0l(s)/T(s). [Sec- tion: 2.7] 2 N-m-s/rad 3 N-m/rad N2= 33 1 kg-m2 HU 00002N3 = 50 nT(1) ne (1) A N, = 11 N4= 101 0.04 ...

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