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Determine the free vibration response of the 3-storey frame above subject to the following initial conditions and damping ratio. Plot the modal response of each natural mode as well as the total response for the whole system.
Determine the free vibration response of the 3-storey frame above subject to the following initial conditions and damping ratio. Plot the modal response of each natural mode as well as the total response for the whole system.

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The figure below shows an embankment, which is constructed using soil with an undrained shear strength of 70 kPa. Please evaluate the stability of the embankment with the shown circular slip surface in the figure below when the reservoir has been completely emptied. (10 marks) 20m -30m tomy – R-412m 148m 2 m -am total mass of block 720 Mg/in Sm undrained cohesion Cu 70 kN/m2 6m
The figure below shows an embankment, which is constructed using soil with an undrained shear strength of 70 kPa. Please evaluate the stability of the embankment with the shown circular slip surface in the figure below when the reservoir has ...

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a) Determine the total resistance through the wall b)the heat flow rate c)  temperature variation at a length of 1.75cm  

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Water of density ρ = 998 kg m−3 and kinematic viscosity ν = 0.01 cm2 s −1 flows through a split nozzle, and exits to the standard sea-level atmosphere of pressure p = 101325 N m−2 , as shown in Figure 1. The angles between the exit ducts and the horizontal duct are 30◦ . The duct area at section 1 is A1 = 0.02 m2 , and at sections 2 and 3 are A2 = A3 = 0.008 m2 . The pressure at section 1 is p1 = 135000 N m−2 , and the volumetric flow rates at sections 2 and 3 are Q2 = Q3 = 275 m3 h −1 .
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A viscous fluid of constant density ρ and dynamic viscosity μ falls due to gravity between two plates a distance 2h apart, as shown in Figure 2. The flow is fully developed, with a single velocity component  = (). There are no applied pressure gradients, and gravity is the only body force. The extensions of each plate along the y and z directions are Ly and Lz correspondingly.
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