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Analyze the following beam to determine the member end moments and reactions with 1 inches settlement at support B, by slope-deflection method. Also draw bending moment and shear force diagrams
♥Analyze the following beam to determine the member end moments and reactions with 1 inches settlement at support B, by slope-deflection method. Also draw bending moment and shear force diagrams

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4. Bar ABC shown in Figure 4 is made from plastic having modulus of elasticity, E = 4.0 GPa. The bar consists of two segments, AB and BC. The diameter of segments AB and BC are d1 = 100 mm and d2 = 60 mm, respectively. A longitudinal hole of diameter d is drilled through segment AB for one half of its length (250 mm). If the shortening (contraction) of bar ABC is limited to 8.0 mm, determine; i. Draw the free – body diagram (F.B.DO and determine the deformation of segment BC. (4 marks) ii. Calculate the maximum allowable diameter dmax of the hole. (6 marks)
4. Bar ABC shown in Figure 4 is made from plastic having modulus of elasticity, E = 4.0 GPa. The bar consists of two segments, AB and BC. The diameter of segments AB and BC are d1 = 100 mm ...

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. Design the longitudinal and circumferential joint for a boiler whose diameter is 2.4 metres and is subjected to a pressure of 1 N/mm2. The longitudinal joint is a triple riveted butt joint with an efficiency of about 85% and the circumferential joint is a double riveted lap joint with an efficiency of about 70%. The pitch in the outer rows of the rivets is to be double than in the inner rows and the width of the cover plates is unequal. The allowable stresses are: σt = 77 MPa ; τ = 56 MPa and σc = 120 MPa. Assume that the resistance of rivets in double shear is 1.875 times that of single shear. Draw the complete joint
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Find a general solution to the differential equation. [ y^{prime prime}(theta)+12 y^{prime}(theta)+37 y(theta)=2 e^{-6 theta} cos theta ] The general solution is y(θ)=
Find a general solution to the differential equation. [ y^{prime prime}(theta)+12 y^{prime}(theta)+37 y(theta)=2 e^{-6 theta} cos theta ] The general solution is y(θ)=

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