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A 5-m long simply supported timber beam carries a uniformly distributed load of 12 kN/m, as shown in Figure P9.11a. The cross-sectional dimensions of the beam are shown in Figure P9.11b. (a) At section a-a, determine the magnitude of the shear stress in the beam at point H. (b) At section a-a, determine the magnitude of the shear stress in the beam at point K. (c) Determine the maximum horizontal shear stress that occurs in the beam at any location within the 5-m span length. (d) Determine the maximum compression bending stress that occurs in the beam at any location within the 5-m span length
A 5-m long simply supported timber beam carries a uniformly distributed load of 12 kN/m, as shown in Figure P9.11a. The cross-sectional dimensions of the beam are shown in Figure P9.11b. (a) At section a-a, determine the magnitude of the shear ...

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A 5-m long simply supported timber beam carries a uniformly distributed load of 12 kN/m, as shown in Figure P9.11a. The cross-sectional dimensions of the beam are shown in Figure P9.11b. (a) At section a-a, determine the magnitude of the shear stress in the beam at point H. (b) At section a-a, determine the magnitude of the shear stress in the beam at point K. (c) Determine the maximum horizontal shear stress that occurs in the beam at any location within the 5-m span length. (d) Determine the maximum compression bending stress that occurs in the beam at any location within the 5-m span length
A 5-m long simply supported timber beam carries a uniformly distributed load of 12 kN/m, as shown in Figure P9.11a. The cross-sectional dimensions of the beam are shown in Figure P9.11b. (a) At section a-a, determine the magnitude of the shear ...

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*4–156. Determine the length b of the triangular load and its position a on the beam such that the equivalent resultant force is zero and the resultant couple moment is 8 kN # m clockwise.
*4–156. Determine the length b of the triangular load and its position a on the beam such that the equivalent resultant force is zero and the resultant couple moment is 8 kN # m clockwise.

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4–155. Replace the distributed loading by an equivalent resultant force and specify where its line of action intersects a vertical line along member BC, measured from C.
4–155. Replace the distributed loading by an equivalent resultant force and specify where its line of action intersects a vertical line along member BC, measured from C.

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4–154. Replace the distributed loading by an equivalent resultant force and specify where its line of action intersects a horizontal line along member AB, measured from A.

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