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P4.10. The following table* gives the stress-strain data for [0/90/+45]s and [0/90]2s AS-4 carbon fiber-epoxy laminates obtained in a three-rail shear test. Plot the data and determine the shear modulus for each laminate. Compare these values with those predicted by the lamination 143.92 GPa, theory based on the following material properties: E11 E22 11.86 GPa, G12 = 6.68 GPa, and V12 = 0.326. Shear Stress (MPa) [0/90/+45)s [0/90)2s Shear Strain (%) 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 40 91 128.6 155 178 208 232 260 13.6 24.5 37 47.3 54.5 62 65.4 70
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Fernando01
![P4.10. The following table* gives the stress-strain data for [0/90/+45]s and [0/90]2s AS-4 carbon fiber-epoxy laminates obtained in a three-rail shear test. Plot the data and determine the shear modulus for each laminate. Compare these values with those predicted by the lamination 143.92 GPa, theory based on the following material properties: E11 E22 11.86 GPa, G12 = 6.68 GPa, and V12 = 0.326. Shear Stress (MPa) [0/90/+45)s [0/90)2s Shear Strain (%) 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 40 91 128.6 155 178 208 232 260 13.6 24.5 37 47.3 54.5 62 65.4 70](https://numengineering.com/wp-content/uploads/2025/02/phpOVTzxG.png)
P4.10. The following table* gives the stress-strain data for [0/90/+45]s and [0/90]2s AS-4 carbon fiber-epoxy laminates obtained in a three-rail shear test. Plot the data and determine the shear modulus for each laminate. Compare these values with those predicted by ...
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The following longitudinal tensile strength data (in MPa) were obtained for a [0/+45/90], E-glass fiber-epoxy laminate: 518.05, 472.25, 448.50, 560.20, 555.32, 496.95, 526.50, 550.80, 495.08, 500.05, 498.80, 522.64, and 580.70. (a) Determine the average tensile strength, the standard deviation, and coefficient of variation (b) Determine the Weibull parameters for the given strength distribution (c) Using the Weibull parameters in (b), determine the mean strength for the material
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Fernando01
The following longitudinal tensile strength data (in MPa) were obtained for a [0/+45/90], E-glass fiber-epoxy laminate: 518.05, 472.25, 448.50, 560.20, 555.32, 496.95, 526.50, 550.80, 495.08, 500.05, 498.80, 522.64, and 580.70. (a) Determine the average tensile strength, the standard deviation, and ...
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The following longitudinal tensile strength data (in MPa) were obtained for a [0/+45/90], E-glass fiber-epoxy laminate: 518.05, 472.25, 448.50, 560.20, 555.32, 496.95, 526.50, 550.80, 495.08, 500.05, 498.80, 522.64, and 580.70. (a) Determine the average tensile strength, the standard deviation, and coefficient of variation (b) Determine the Weibull parameters for the given strength distribution (c) Using the Weibull parameters in (b), determine the mean strength for the material
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Fernando01
The following longitudinal tensile strength data (in MPa) were obtained for a [0/+45/90], E-glass fiber-epoxy laminate: 518.05, 472.25, 448.50, 560.20, 555.32, 496.95, 526.50, 550.80, 495.08, 500.05, 498.80, 522.64, and 580.70. (a) Determine the average tensile strength, the standard deviation, and ...
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A T-300 carbon fiber-epoxy lamina (Vf = 0.60) with a fiber orientation angle of 45student submitted image, transcription available belowis subjected to a biaxial stress state ofstudent submitted image, transcription available belowxx = 100 MPa andstudent submitted image, transcription available belowyy = -50 MPa. Determine (a) the strains in the x-y directions, (b) the strains in the 1-2 directions, and (c) the stresses in the 1-2 directions.
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Fernando01
A T-300 carbon fiber-epoxy lamina (Vf = 0.60) with a fiber orientation angle of 45is subjected to a biaxial stress state ofxx = 100 MPa and
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P3.27. The material used in the transmission gears of an automobile is an injection-molded nylon 6,6 containing 20 wt% of chopped randomly oriented E-glass fibers. The tensile modulus of this material is 1.25 × 10° psi. In a more demanding application for the transmission gears, the modulus of the material must be 50% higher. An engineer wants to accomplish this by replacing the E-glass fibers with carbon fibers. If the fiber weight fraction remains the same, calculate the length of carbon fibers that must be used to obtain the desired modulus Use the following information in your calculations. (a) For the carbon fiber, Pr= 1.8 g/cm. Ef= 30 × 106 psi, and df= 0.0006 in, and (b) for nylon 6,6, Pm-114 g/cm 3 and Em-0.4 × 106 psi
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Fernando01
P3.27. The material used in the transmission gears of an automobile is an injection-molded nylon 6,6 containing 20 wt% of chopped randomly oriented E-glass fibers. The tensile modulus of this material is 1.25 × 10° psi. In a more demanding ...
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A round tube (outside diameter ¼ 25 mm, wall thickness ¼ 2.5 mm, and length ¼ 0.5 m) is made by wrapping continuous AS-4 carbon fiberreinforced epoxy layers, all in the hoop direction. The fiber volume fraction is 60%. 1. Determine the change in length and diameter of the tube if it is subjected to an axial tensile load of 2 kN 2. Determine the maximum axial tensile load that can be applied on the tube? 3. Suppose the tube is used in a torsional application. What will be its torsional stiffness (torque per unit angle of twist)? The modulus, tensile strength, and Poisson’s ratio of the epoxy matrix are 5 GPa, 90 MPa, and 0.34, respectively.
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Fernando01
A round tube (outside diameter ¼ 25 mm, wall thickness ¼ 2.5 mm, and length ¼ 0.5 m) is made by wrapping continuous AS-4 carbon fiberreinforced epoxy layers, all in the hoop direction. The fiber volume fraction is 60%. 1. ...
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P3.13. The interfacial shear strength of a fiber-matrix joint is often measured by a pullout test. This involves pulling a fiber bundle out of a resin disk cast around a small length of the bundle. A typical load displacement curve obtained in a pullout test is shown. 1. Calculate the average interfacial shear strength of the joint 2. What must the maximum thickness of the resin disk be so that the fiber bundle pulls out before it breaks within the disk? Pmax Load (P) Displacement sin di Fiber bundle
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Fernando01
P3.13. The interfacial shear strength of a fiber-matrix joint is often measured by a pullout test. This involves pulling a fiber bundle out of a resin disk cast around a small length of the bundle. A typical load displacement curve ...
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P3.6. A unidirectional continuous fiber lamina is subjected to shear stress as shown in the following figure. Using the “slab” model, show that the shear modulus GLt of the lamina can be represented by the following equation. 1 GLT = VE (1 – Vf) + GE Gm Matrix Fiber Unidirectional continuous fiber-reinforced composite and the equivalent slab model in in-plane shear loading
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Fernando01
P3.6. A unidirectional continuous fiber lamina is subjected to shear stress as shown in the following figure. Using the “slab” model, show that the shear modulus GLt of the lamina can be represented by the following equation. 1 GLT = ...
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The following data were obtained in a resin burn-off test of an E-glass-polyester sample: Weight of an crucible = 10.1528g, Weight of crucible + sample before burn off = 10.5219g, Weight of crucible + sample after burn off = 10.3221g. Calculate the fiber weight fraction, the fiber volume fraction, and the density of the composite sample. Assume Pf = 2.54g/ml, and Pm = 1.25g/ml. Do you expect the calculated value to be higher or lower than the actual value? tips: Vf = ((Wf/Pf))/((Wf/Pf) + (1-Wf)/Pm) Pc = (1)/((Wf/Pf) + (1-Wf)/Pm)
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Fernando01
The following data were obtained in a resin burn-off test of an E-glass-polyester sample: Weight of an crucible = 10.1528g, Weight of crucible + sample before ...