Engineering Mechanics Chapter 1

Step-by-Step Solution Step 1 We are given the units ${\rm{8653}}\;{\rm{ms}}$, $8368\;{\rm{N}}$ and $0.893\;{\rm{kg}}$. We are asked to represent the SI units. Step 2 (a) To find the SI unit we need to reduce the combinations of units. Since ${\rm{1 ms}} = {\rm{1}}{{\rm{0}}^{ – 3}}\,{\rm{s}}$, then\[\begin{array}{c} {\rm{8653}}\;{\rm{ms}} = \left( {{\rm{8}}{\rm{.653}} \times {\rm{1}}{{\rm{0}}^3}\;{\rm{ms}}} \right)\left( {\frac{{{\rm{1}}{{\rm{0}}^{ – 3}}\,{\rm{s}}}}{{{\rm{1}}\;{\rm{ms}}}}} […]

Step-by-Step Solution Step 1 We are given the units ${\rm{GN}} \cdot {\rm{\mu m}}$, ${\rm{kg/\mu m}}$, ${\rm{N/k}}{{\rm{s}}^2}$ and ${\rm{kN/\mu s}}$. We are asked to estimate the correct SI form of the units. Step 2 (a) To find the SI form of unit ${\rm{GN}} \cdot {\rm{\mu m}}$ we need to reduce the combinations of units. Since $1\;{\rm{GN}}

Step-by-Step Solution Step 1 We are given the units ${\rm{m/ms}}$, ${\rm{\mu km}}$, ${\rm{ks/mg}}$ and ${\rm{km}} \cdot {\rm{\mu N}}$. We are asked to estimate the correct SI form of the units. Step 2 (a) To find the SI form of unit ${\rm{m/ms}}$ we need to reduce the combinations of units. Since $1\;{\rm{ms}} = {\rm{1}}{{\rm{0}}^{ – 3}}\,{\rm{s}}$,

Step-by-Step Solution Step 1 We are given the units ${\rm{Mg/mm}}$, ${\rm{mN/\mu s}}$ and ${\rm{\mu m}} \cdot {\rm{Mg}}$. We are asked to estimate the correct SI form of the units. Step 2 (a) To find the SI form of unit ${\rm{Mg/mm}}$ we need to reduce the combinations of units. Since $1\;{\rm{Mg}} = {\rm{1}}{{\rm{0}}^3}\,{\rm{kg}}$ and $1\;{\rm{mm}} =

Step-by-Step Solution Step 1 We are given the values $0.000431\;{\rm{kg}}$, $35.3\left( {{{10}^3}} \right)\;{\rm{N}}$ and $0.00532\;{\rm{km}}$. We are asked to represent each of the given values in the correct SI form. Step 2 (a) To convert the quantities into correct SI form we will use the following relation. Since $1\;{\rm{kg}} = {10^3}\,{\rm{g}}$, then\[\begin{array}{c} 0.000431\;{\rm{kg}} = \left(

Step-by-Step Solution Step 1 We are given the values $58342\;{\rm{m}}$, $68.534\;{\rm{s}}$, $2553\;{\rm{N}}$ and$7555\;{\rm{kg}}$. We are asked to round off the number to three significant figures. Step 2 (a) To round off the number to three significant figures we will use the following relation. Since ${10^3}\;{\rm{m}} = 1\,{\rm{km}}$, then\[\begin{array}{c} 58342\;{\rm{m}} = \left( {58.342 \times {{10}^3}\;{\rm{m}}} \right)\left(

Step-by-Step Solution Step 1 We are given the values $45320\;{\rm{kN}}$, $568\left( {{{10}^5}} \right)\;{\rm{mm}}$ and $0.00563\;{\rm{mg}}$. We are asked to represent the number between 0.1 and 1000 using an appropriate prefix. Step 2 (a) To represent the number between 0.1 and 1000 we will use the following relation. Since $1000\;{\rm{kN}} = 1\,{\rm{MN}}$, then\[\begin{array}{c} 45320\;{\rm{kN}} = \left(

Step-by-Step Solution Step 1 We are given the values ${\rm{200}}\;{\rm{lb}} \cdot {\rm{ft}}$, ${\rm{350}}\;{\rm{lb/f}}{{\rm{t}}^3}$ and$8\;{\rm{ft/h}}$. We are asked toconvert the units of given values. Step 2 (a) To convert the unit into SI form we will use the following relation. Since $1\;{\rm{lb}} = 4.448\,{\rm{N}}$ and $1\;{\rm{ft}} = 0.3048\;{\rm{m}}$, then\[\begin{array}{c} {\rm{200}}\;{\rm{lb}} \cdot {\rm{ft}} = \left( {200\;{\rm{lb}} \cdot

Step-by-Step Solution Step 1 We are given the units ${\rm{Mg/ms}}$, ${\rm{N/mm}}$and ${\rm{mN/}}\left( {{\rm{kg}} \cdot {\rm{\mu s}}} \right)$. We are asked to estimate the correct SI form of the units. Step 2 (a) To find the SI form of unit ${\rm{Mg/ms}}$ we need to reduce the combinations of units. Since $1\;{\rm{Mg}} = {\rm{1}}{{\rm{0}}^3}\,{\rm{kg}}$ and $1\;{\rm{ms}} =

Step-by-Step Solution Step 1 We are given the units ${\rm{kN/\mu s}}$, ${\rm{Mg/mN}}$ and ${\rm{MN/}}\left( {{\rm{kg}} \cdot {\rm{ms}}} \right)$. We are asked to estimate the correct SI form of the units. Step 2 (a) To find the SI form of unit ${\rm{kN/\mu s}}$ we need to reduce the combinations of units. Since $1\;{\rm{kN}} = {\rm{1}}{{\rm{0}}^3}\,{\rm{N}}$ and