Ali Raza

Step-by-Step Solution Step 1 We are given that the density of the water is ${\rho _w} = 1.94\;{\rm{slug/f}}{{\rm{t}}^3}$ We are asked to determine the density of water in SI units. Step 2 The mass $1\;{\rm{slug}}$ is equal to $14.59\;{\rm{kg}}$ in SI units, and the length $1\;{\rm{ft}}$ is equal to $0.3048\;{\rm{m}}$. Step 3 Now, convert the […]

Step-by-Step Solution Step 1 We have the relation $1\;{\rm{Pa}} = 1\;{\rm{N/}}{{\rm{m}}^2}$, and the seal level pressure is $14.7\;{{{\rm{lb}}} \mathord{\left/ {\vphantom {{{\rm{lb}}} {{\rm{i}}{{\rm{n}}^2}}}} \right. } {{\rm{i}}{{\rm{n}}^2}}}$. We are required to find the value of $1\;{\rm{Pa}}$ in ${{{\rm{lb}}} \mathord{\left/ {\vphantom {{{\rm{lb}}} {{\rm{f}}{{\rm{t}}^2}}}} \right. } {{\rm{f}}{{\rm{t}}^2}}}$, and the value of sea level pressure in ${{{\rm{lb}}} \mathord{\left/ {\vphantom {{{\rm{lb}}}

Step-by-Step Solution Step 1 We have the equation of force which is given by, $F = G\frac{{{m_1}{m_2}}}{{{r^2}}}$ We have the mass of each sphere, that is ${m_1} = {m_2} = 200\;{\rm{kg}}$. The radius of each sphere is: ${r_s} = 300\;{\rm{mm}}$ We are required to show that the given equation is dimensionally homogeneous. Also, we are

Step-by-Step Solution Step 1 The given physical quantities are ${\left( {212\;{\rm{mN}}} \right)^2},\;{\left( {52800\;{\rm{ms}}} \right)^2}$ and ${\left[ {548\left( {{{10}^6}} \right)} \right]^{{1 \mathord{\left/ {\vphantom {1 2}} \right. } 2}}}\;{\rm{ms}}$ We are required to determine the given physical quantities in SI units in three significant figures. Step 2 The value of $1\;{\rm{mN}}$ is equal to $1 \times {10^{

Step-by-Step Solution Step 1 We are given with the density of Aluminium ${\rho _{Al}} = 5.26\;{\rm{slug/f}}{{\rm{t}}^3}$ We are asked to compute the density of Aluminium in SI units. Step 2 “slug” is the unit of mass, and $1\;{\rm{slug}}$ is equal to $14.59\;{\rm{kg}}$ of SI units. Whereas, “ft” or feet is the unit of length, and

Step-by-Step Solution Step 1 We are given the units $\left( {684\;{\rm{\mu m}}} \right)/\left( {43\;{\rm{ms}}} \right)$, $\left( {{\rm{28}}\;{\rm{ms}}} \right)\left( {{\rm{0}}{\rm{.0458}}\;{\rm{Mm}}} \right){\rm{/}}\left( {348\;{\rm{mg}}} \right)$ and $\left( {2.68\;{\rm{mm}}} \right)\left( {426\;{\rm{Mg}}} \right)$. We are asked to evaluate each of the following significant figure and SI units. Step 2 (a) To find the SI unit we need to use the

Step-by-Step Solution Step 1 We are given the units ${\rm{8653}}\;{\rm{ms}}$, $8368\;{\rm{N}}$ and $0.893\;{\rm{kg}}$. We are asked to represent the SI units. Step 2 (a) To find the SI unit we need to reduce the combinations of units. Since ${\rm{1 ms}} = {\rm{1}}{{\rm{0}}^{ – 3}}\,{\rm{s}}$, then\[\begin{array}{c} {\rm{8653}}\;{\rm{ms}} = \left( {{\rm{8}}{\rm{.653}} \times {\rm{1}}{{\rm{0}}^3}\;{\rm{ms}}} \right)\left( {\frac{{{\rm{1}}{{\rm{0}}^{ – 3}}\,{\rm{s}}}}{{{\rm{1}}\;{\rm{ms}}}}}

Step-by-Step Solution Step 1 We are given the units ${\rm{GN}} \cdot {\rm{\mu m}}$, ${\rm{kg/\mu m}}$, ${\rm{N/k}}{{\rm{s}}^2}$ and ${\rm{kN/\mu s}}$. We are asked to estimate the correct SI form of the units. Step 2 (a) To find the SI form of unit ${\rm{GN}} \cdot {\rm{\mu m}}$ we need to reduce the combinations of units. Since $1\;{\rm{GN}}

Step-by-Step Solution Step 1 We are given the units ${\rm{m/ms}}$, ${\rm{\mu km}}$, ${\rm{ks/mg}}$ and ${\rm{km}} \cdot {\rm{\mu N}}$. We are asked to estimate the correct SI form of the units. Step 2 (a) To find the SI form of unit ${\rm{m/ms}}$ we need to reduce the combinations of units. Since $1\;{\rm{ms}} = {\rm{1}}{{\rm{0}}^{ – 3}}\,{\rm{s}}$,

Step-by-Step Solution Step 1 We are given the units ${\rm{Mg/mm}}$, ${\rm{mN/\mu s}}$ and ${\rm{\mu m}} \cdot {\rm{Mg}}$. We are asked to estimate the correct SI form of the units. Step 2 (a) To find the SI form of unit ${\rm{Mg/mm}}$ we need to reduce the combinations of units. Since $1\;{\rm{Mg}} = {\rm{1}}{{\rm{0}}^3}\,{\rm{kg}}$ and $1\;{\rm{mm}} =