Step-by-Step Solution Step 1 We are given the value of resultant force ${{\bf{F}}_R} = {{\bf{F}}_1} + {{\bf{F}}_2}$. We are asked to estimate the magnitudes of the resultant force. Step 2 The following is the diagram from the parallelogram law of addition. The diagram of the resultant force is as follows: Step 3 The relation from […]
Step-by-Step Solution Step 1 We are given the value of force $F = 3{\rm{50 lb}}$. We are asked to estimate the magnitudes of the two components of F. Step 2 The relation to convert the force from pound into newton is, Since $1\;{\rm{lb}} = {\rm{4}}{\rm{.448}}\;{\rm{N}}$, then\begin{array}{c} 3{\rm{50 lb}} = \left( {350\;{\rm{lb}} \times \frac{{{\rm{4}}{\rm{.448}}\;{\rm{N}}}}{{1\;{\rm{lb}}}}} \right)\\ =
Solve Prob. 2–4 with F = 350 lb. Read More »
Step-by-Step Solution Step 1 We are given the value of force $F = {\rm{500 N}}$. We are asked to estimate the magnitudes of the two components of F. Step 2 The following is the free body diagram to calculate the magnitude of force related to link AB. To find the magnitude of force we will
Step-by-Step Solution Step 1 We are given the force ${F_R} = {F_1} + {F_2}$,${F_1} = 250\;{\rm{lb}}$ and ${F_2} = 375\;{\rm{lb}}$. We are asked to determine the magnitude and direction of the resultant force. Step 2 The following is the diagram to calculate the projected component of the force. To find the magnitude of the resultant
Step-by-Step Solution Step 1 We are given the force ${F_R} = 500\;{\rm{N}}$ and ${F_1} = 700\;{\rm{N}}$. We are asked to determine the magnitude of force ${\bf{F}}$ and its direction ${\bf{\theta }}$. Step 2 The following is the diagram of the vector component. The following is the diagram of the vector component tail to tail. Step
Step-by-Step Solution Step 1 Given that the angle $\theta $ is $60^\circ $, and the force $F = 450\;{\rm{N}}$. We are required to determine the resultant force and its direction measured counter clockwise from the positive $x$ -axis. Step 2 We have to make the parallel lines from the force vectors to get a parallelogram.
Step-by-Step Solution Step 1 Given that the mass of first particle is $8\;{\rm{kg}}$ and the mass of second particle is $12\;{\rm{kg}}$. Also the spacing between the particles is $800\;{\rm{mm}}$ We are required to determine the gravitational force between particles and we need to compare the force with weights. Step 2 The length $1\;{\rm{mm}}$ is equal
Step-by-Step Solution Step 1 Given that the weight of the man on Earth is $155\;{\rm{lb}}$, and the acceleration due to gravity on the moon is ${g_m} = 5.30\;{\rm{ft/}}{{\rm{s}}^2}$. We are required to find out the mass of man on Earth in slugs, kilograms and man’s weight in Newton. Also it is required to find out
Step By Step Solution Step 1 We have the given diameter $350\;{\rm{mm}}$, length $2\;{\rm{m}}$, and the density of the concrete $2.45\;{{{\rm{Mg}}} \mathord{\left/ {\vphantom {{{\rm{Mg}}} {{{\rm{m}}^3}}}} \right. } {{{\rm{m}}^3}}}$. We are required to determine the weight of column in pounds. Step 2 Convert the unit of diameter $\left( d \right)$ into SI units.\[\begin{array}{c} d = 350\;{\rm{mm}}\\
Step-by-Step Solution Step 1 The given quantities are (a) ${{354\;{\rm{mg}}\left( {45\;{\rm{km}}} \right)} \mathord{\left/ {\vphantom {{354\;{\rm{mg}}\left( {45\;{\rm{km}}} \right)} {\left( {0.0356\;{\rm{kN}}} \right)}}} \right. } {\left( {0.0356\;{\rm{kN}}} \right)}}$, (b) $\left( {0.00453\;{\rm{Mg}}} \right)\left( {201\;{\rm{ms}}} \right)$, and (c) ${{435\;{\rm{MN}}} \mathord{\left/ {\vphantom {{435\;{\rm{MN}}} {23.2\;{\rm{mm}}}}} \right. } {23.2\;{\rm{mm}}}}$ We are asked to determine the value of given quantities in SI units in
