Problem 8-5 Chapter 8 · Section 8.2 · 0 views

A $25,mathrm{kg}$ block rests on a rough horizontal surface. A horizontal force $P = 80,mathrm{N}$ is applied. If $mu_s = 0.35$, determine whether the block moves and find the friction force.

Step-by-step solution4 steps · expert verified
  1. 1

    Draw the free-body diagram

    Isolate the block: weight $W=mg$ down, normal $N$ up, applied $P$ to the right, friction $f$ opposing motion.

    mNW = mgPfFig. Free-body diagram of the block
  2. 2

    Vertical equilibrium

    [ Sigma F_y = 0:; N - mg = 0 Rightarrow N = (25)(9.81) = 245.25,mathrm{N} ]

  3. 3

    Maximum static friction

    [ f_{max} = mu_s N = 0.35times 245.25 = 85.84,mathrm{N} ] Since $P=80,mathrm{N} < f_{max}$, the block does not move.

  4. 4

    Actual friction force

    [ Sigma F_x = 0:; f = P = 80,mathrm{N} ] The block stays at rest, $f = 80,mathrm{N}$ opposite to $P$.

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static friction block problem coefficient of static friction 0.35 does the block move equilibrium friction force

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