Draw the free-body diagram
Isolate the block: weight $W=mg$ down, normal $N$ up, applied $P$ to the right, friction $f$ opposing motion.
Vertical equilibrium
[ Sigma F_y = 0:; N - mg = 0 Rightarrow N = (25)(9.81) = 245.25,mathrm{N} ]
Maximum static friction
[ f_{max} = mu_s N = 0.35times 245.25 = 85.84,mathrm{N} ] Since $P=80,mathrm{N} < f_{max}$, the block does not move.
Actual friction force
[ Sigma F_x = 0:; f = P = 80,mathrm{N} ] The block stays at rest, $f = 80,mathrm{N}$ opposite to $P$.
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